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Can anyone figure this out?


poz
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Assume:

a in {1..9}

b in {0..9}

x = 10a + b

Solve:

x - a - b = y

(10a + b) - a - b = y

Therefore

9a = y

It follows that y is always a multiple of 9.

If you put the same value in all squares represented by a multiple of 9 (i.e. 9, 18, 27 ... 81) and randomize all other values you're guaranteed to always be correct.

... couldn't help myself.

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Assume:

a in {1..9}

b in {0..9}

x = 10a + b

Solve:

x - a - b = y

(10a + b) - a - b = y

Therefore

9a = y

It follows that y is always a multiple of 9.

If you put the same value in all squares represented by a multiple of 9 (i.e. 9, 18, 27 ... 81) and randomize all other values you're guaranteed to always be correct.

... couldn't help myself.

jesus dean.....have you entered the krypton factor this year!! lol

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